32x^4-4x^2/8

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Solution for 32x^4-4x^2/8 equation: 


x in (-oo:+oo)

32*x^4-((4*x^2)/8) = 0

32*x^4+(-1/2)*x^2 = 0

32*x^4-1/2*x^2 = 0

t_1 = x^2

32*t_1^2-1/2*t_1^1 = 0

32*t_1^2-1/2*t_1 = 0

DELTA = (-1/2)^2-(0*4*32)

DELTA = 1/4

DELTA > 0

t_1 = ((1/4)^(1/2)+1/2)/(2*32) or t_1 = (1/2-(1/4)^(1/2))/(2*32)

t_1 = 1/64 or t_1 = 0

t_1 = 0

x^2+0 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

t_1 = 1/64

x^2-1/64 = 0

1*x^2 = 1/64 // : 1

x^2 = 1/64

x^2 = 1/64 // ^ 1/2

abs(x) = 1/8

x = 1/8 or x = -1/8

x in { 0, 1/8, -1/8 }

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